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e2bmef4w
@e2bmef4w
June 2021
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pourriez vous m'aider svp
ex 28
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slyz007
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1) Forme 1 : 4(x-5)²-9=4(x²-10x+25)-9=4x²-40x+91 = forme 3
Forme 2 : (2x-13)(2x-7)=4x²-14x-26x+91=4x²-40x+91 = forme 3
2) La forme factorisée de f est la forme 2
3a) On utilise la forme 2 : (2x-13)(2x-7)=0
⇔(2x-13)=0 ou (2x-7)=0
⇔2x=13 ou 2x=7
⇔x=13/2 ou x=7/2
3b) On utilise la forme 3 : f(0)=4*0²-40*0+91=91
3c) On utilise la forme 1 : f(x)=-9
⇔4(x-5)²-9=-9
⇔4(x-5)²=0
⇔x-5=0
⇔x=5
3d) On utilise la forme 3 : f(√2)=4*2-40√2+91=99-40√2
3e) On utilise la forme 3 : f(x)=91
⇔4x²-40x+91=91
⇔4x²-40x=0
⇔x(x-10)=0
⇔x=0 ou x=10
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1) Forme 1 : 4(x-5)²-9=4(x²-10x+25)-9=4x²-40x+91 = forme 3Forme 2 : (2x-13)(2x-7)=4x²-14x-26x+91=4x²-40x+91 = forme 3
2) La forme factorisée de f est la forme 2
3a) On utilise la forme 2 : (2x-13)(2x-7)=0
⇔(2x-13)=0 ou (2x-7)=0
⇔2x=13 ou 2x=7
⇔x=13/2 ou x=7/2
3b) On utilise la forme 3 : f(0)=4*0²-40*0+91=91
3c) On utilise la forme 1 : f(x)=-9
⇔4(x-5)²-9=-9
⇔4(x-5)²=0
⇔x-5=0
⇔x=5
3d) On utilise la forme 3 : f(√2)=4*2-40√2+91=99-40√2
3e) On utilise la forme 3 : f(x)=91
⇔4x²-40x+91=91
⇔4x²-40x=0
⇔x(x-10)=0
⇔x=0 ou x=10