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Sousou299
@Sousou299
May 2019
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Pouvez m’aider s’il vous plaît au équations et aux inéquations suivantes merci d’avance c’est pour mon dm de math;
16x2-8x+1=0
4x+8=x-9
x-7 9x>11
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swnn
Verified answer
16x²-8x+1=0
(4x-1)²=0; donc:
4x-1=0
4x=1
x=1/4
4x+8 = x-9
4x-x = -9-8
3x = -17
x =-17/3
0 votes
Thanks 0
Commentaires
Bonjour,
16x^2-8x+1=0
(4x)^2-2*4x*1+(1)^2=0
(4x-1)^2=0
4x-1=0
4x=1
x= 1/4
4x+8=x-9
4x+8-8=x-9-8
4x = x-17
4x-x=x-17-x
3x = -17
3x/3 = -17/3
x =~ -5,7 (arrondi)
2 votes
Thanks 1
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Verified answer
16x²-8x+1=0(4x-1)²=0; donc:
4x-1=0
4x=1
x=1/4
4x+8 = x-9
4x-x = -9-8
3x = -17
x =-17/3
16x^2-8x+1=0
(4x)^2-2*4x*1+(1)^2=0
(4x-1)^2=0
4x-1=0
4x=1
x= 1/4
4x+8=x-9
4x+8-8=x-9-8
4x = x-17
4x-x=x-17-x
3x = -17
3x/3 = -17/3
x =~ -5,7 (arrondi)