@bmayumis

bmayumis

Ambicioso

1. Calcule [tex]y= arctg\sqrt[2]{3} + arcsen\frac{1}{2}[/tex]·[tex]arccos\frac{1}{2}[/tex] 2. Se [tex]x= arccos(\frac{-\sqrt{3} }{2} )[/tex] , qual é o valor de cos (10x)?
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Resolva: sen 140° · sec 310°
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