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NinidreamSs
@NinidreamSs
April 2019
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Quelques pourrait m'aider pour la question 3 a et b ?
Je sais que pour trouver l'équation c'est
y=f'(a)(x-a)+f (a)
Mais je pense que ce que j'ai trouvé n'est pas bon :(
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anylor
Verified answer
Oui tu as la bonne formule
la tangente = 2 -2ln(2) -ln(2) (x-2)
= - x ln(2) +2
pour les coordonnées de A'
x=0 => y = 2
A' ( 0 ;2)
2 votes
Thanks 1
danielwenin
La réponse en fichier joint
1 votes
Thanks 1
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Verified answer
Oui tu as la bonne formulela tangente = 2 -2ln(2) -ln(2) (x-2)
= - x ln(2) +2
pour les coordonnées de A'
x=0 => y = 2
A' ( 0 ;2)