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yayane97
@yayane97
January 2021
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Quelqu'un peut m'aider pour un devoir de physique chimie en 1ere S s'il vous plaît
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scoladan
Verified answer
Bonjour,
1)
Na₂S₂O₃ → 2Na⁺ + S₂O₃²⁻
2) d'après l'équation :
[Na⁺] = 2 x [S₂O₃²⁻]
⇒ [S₂O₃²⁻] = 1,0.10⁻²/2 = 0,5.10⁻² mol.L⁻¹
3) de même : C = [Na⁺]/2 = 0,5.10⁻² mol.L⁻¹
4) M(Na₂S₂O₃] = 2xM(Na) + 2xM(S) + 3xM(O)
= 2x23,1 + 2x32,1 + 3x16
= 158,4 g.mol⁻¹
n = C x V = 0,5.10⁻² x 100.10⁻³ = 5.10⁻⁴ mol
Donc m = n x M = 5.10⁻⁴ x 158,4 = 0,0792 g
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Verified answer
Bonjour,1)
Na₂S₂O₃ → 2Na⁺ + S₂O₃²⁻
2) d'après l'équation :
[Na⁺] = 2 x [S₂O₃²⁻]
⇒ [S₂O₃²⁻] = 1,0.10⁻²/2 = 0,5.10⁻² mol.L⁻¹
3) de même : C = [Na⁺]/2 = 0,5.10⁻² mol.L⁻¹
4) M(Na₂S₂O₃] = 2xM(Na) + 2xM(S) + 3xM(O)
= 2x23,1 + 2x32,1 + 3x16
= 158,4 g.mol⁻¹
n = C x V = 0,5.10⁻² x 100.10⁻³ = 5.10⁻⁴ mol
Donc m = n x M = 5.10⁻⁴ x 158,4 = 0,0792 g