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Mini11
@Mini11
April 2019
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Résoudre cette equation
x(-2x+3)+x(x+2)=0
(7x+3)(2x+1)-x(7x+3)=0
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Lau16
X(-2x + 3) + x(x + 2) = 0
-2x² + 3x + x² + 2x = 0
x² + 5x = 0
x(x + 5) = 0
Soit :
x = 0
Soit : x+5 = 0
x = -5
(7x + 3)(2x + 1) - x(7x + 3) = 0
(7x + 3)(2x + 1 - x) = 0
(7x + 3)(x + 1) = 0
Soit : 7x + 3 = 0
7x = -3
x = -
Soit : x + 1 = 0
x = -1
0 votes
Thanks 0
Commentaires (9)
-2x+3x+x²+2x = 0
x²+3x = 0
x(x+3) = 0
x+3 = 0
x = -3
x = 0
on factorise :
(7x+3)(2x+1-x) = 0
(7x+3)(x+1) = 0
7x+3 =0
7x =-3
x =-3/7
x+1 = 0
x = -1
0 votes
Thanks 0
Lau16
Tu n'aurais pas oublié le "²" de ton premier "-2x" ?
Lau16
Et le (7x + 3) de la fin de la deuxième équation, où est-elle présentée dans ta factorisation ?
Lau16
Ha.. Ca arrive ;)
Lau16
Ah oui effectivement ! :)
Lau16
Merci beaucoup :p
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Lista de comentários
-2x² + 3x + x² + 2x = 0
x² + 5x = 0
x(x + 5) = 0
Soit : x = 0
Soit : x+5 = 0
x = -5
(7x + 3)(2x + 1) - x(7x + 3) = 0
(7x + 3)(2x + 1 - x) = 0
(7x + 3)(x + 1) = 0
Soit : 7x + 3 = 0
7x = -3
x = -
Soit : x + 1 = 0
x = -1
x²+3x = 0
x(x+3) = 0
x+3 = 0
x = -3
x = 0
on factorise :
(7x+3)(2x+1-x) = 0
(7x+3)(x+1) = 0
7x+3 =0
7x =-3
x =-3/7
x+1 = 0
x = -1