Résoudre le système d'équations ci-dessous par la méthode de Jacobi et trouver l'intrus, les valeurs inversées et la valeur manquante dans le tableau :
k 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 X33 X₂ x₂ 0 0 0 1,5000000000000 1,1250000000000 0,8437500000000 1,0078125000000 1,0371093750000 0,9887695312500 0,9935302734375 1,0044250488281 1,0005111694336 0,9999999999949 1,0001807212830 1,0002633333206 0,9998889863491 0,9999619200826 1,0000372733921 1,0000002016313 0,9999906312441 1,0000022917811 1,0000017692437 0,9999912847438 0,9999998115031 1,0000003009383 0,9999999718897 1,0000000240793 1,0000000110319 0,9999999912222 0,9999999994365 1,0000000023353 0,9999999995570 9999995269 1,0000000002290 1,0000000000610 099999275 1,0000000000029 1,0000000000174 0,9987659454346 0,9999945999969 1,0000000000020 1,0000000000003 0,999999 99994 1,0000000000001 1,0000000000001 0,999999 19999 1,0000000000000 1,0000000000000 1,0000000000000 1,0000000000000 1,0000000000000 1,000000 00000 1,0000000000000 1,0000000000000 1,0000000000000 1,0000000000000 1,0000000000000 1,0000000000000 1,0000000000000 1,0000000000000 1,0000000000000 1,0000000000000 0,99​