Seja f open parentheses x close parenthesesuma função integrável. Sabendo que F left parenthesis x right parenthesis equals x squared log subscript 2 invisible function application left parenthesis x right parenthesis minus 1 é uma primitiva da f open parentheses x close parenthesesé correto afirmar que: a. integral subscript 1 superscript 2 f left parenthesis x right parenthesis d x equals 2 b. integral subscript 1 superscript 2 f left parenthesis x right parenthesis d x equals 4 c. integral subscript 1 superscript 2 f left parenthesis x right parenthesis d x equals 4 plus log subscript 2 invisible function application left parenthesis e right parenthesis d. integral subscript 1 superscript 2 f left parenthesis x right parenthesis d x equals 5 over 3 minus fraction numerator 7 log subscript 2 invisible function application left parenthesis e right parenthesis over denominator 9 end fraction e. integral subscript 1 superscript 2 f left parenthesis x right parenthesis d x equals 1
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