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SoufianBOUAZAMA
@SoufianBOUAZAMA
April 2019
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Soit f(x) =
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anno32
Bonsoir
Factorisons f(x)
(3/4)x^3 - 6x² + 10x simplifions l'expression en factorisant par x
x ((3/4)x² - 6x + 10 = 0
x = 0 ou ((3/4)x² - 6x + 10 = 0
((3/4)x² - 6x + 10 = 0
Calculons Δ
Δ = b² - 4ac pour a = 3/4, b = -6 et c = 10
Δ = (-6)² - 4(3/4)(10) = 36 - 30 = 6
√Δ = √6
x1 =( -b - √Δ) / 2a
x1 = (6 - √6) / (3/2)
x1 = (12 - 2√6) / 3
x2 = ( -b + √Δ) / 2a
x2 = (6 + √6) / 3/2
x2 = (12 + 2√6) / 3
S = {0;(12 - 2√6) / 3;(12 + 2√6) / 3 }
x(x - 12 +√6)/3)(x-12-√6)/3
2 votes
Thanks 1
SoufianBOUAZAMA
Merci, j'aurais plus souvent besoin de ton aide mais c'est bon pour aujourd'hui :)
anno32
merci à toi aussi
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Lista de comentários
Factorisons f(x)
(3/4)x^3 - 6x² + 10x simplifions l'expression en factorisant par x
x ((3/4)x² - 6x + 10 = 0
x = 0 ou ((3/4)x² - 6x + 10 = 0
((3/4)x² - 6x + 10 = 0
Calculons Δ
Δ = b² - 4ac pour a = 3/4, b = -6 et c = 10
Δ = (-6)² - 4(3/4)(10) = 36 - 30 = 6
√Δ = √6
x1 =( -b - √Δ) / 2a
x1 = (6 - √6) / (3/2)
x1 = (12 - 2√6) / 3
x2 = ( -b + √Δ) / 2a
x2 = (6 + √6) / 3/2
x2 = (12 + 2√6) / 3
S = {0;(12 - 2√6) / 3;(12 + 2√6) / 3 }
x(x - 12 +√6)/3)(x-12-√6)/3