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Hindy59
@Hindy59
April 2019
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Soit x un réel de l'intervalle [ \frac{\pi}{2};\pi] tel que sin x= \frac{ \sqrt{3} }{3}
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danielwenin
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Je suppose qu'il s'agit de résoudre l'équation sinx = √3/3 dans [π/2;π]
x = 0,6154 à rejeter cars hors intervalle donc x = π - 0,6154 = 2,52
bonne journée
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Verified answer
Je suppose qu'il s'agit de résoudre l'équation sinx = √3/3 dans [π/2;π]x = 0,6154 à rejeter cars hors intervalle donc x = π - 0,6154 = 2,52
bonne journée