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1D2010
@1D2010
January 2021
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SVP URGENT!!!
Merci d'avance! !!
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laurance
1)A'=2x-6 s'annule en 3 et a pour minimum A(3)= -1
comme A(2)=A(4)=0 donc -1 < A(x)< 0
2) je pense qu'il n'y a pas plus petit
3) (x-3)² -1 = x² -6x+9-1 = x² -6x +8 = A(x)
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Salut tout le monde! !C vraiment trop urgent! !!Merci d'avance.
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comme A(2)=A(4)=0 donc -1 < A(x)< 0
2) je pense qu'il n'y a pas plus petit
3) (x-3)² -1 = x² -6x+9-1 = x² -6x +8 = A(x)