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ingrid2
@ingrid2
February 2021
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On sait que AH = CH/tan â et que BH = CH/tan b
En partant de l"égalité AB=AH-BH, il faut démontrer que CH = AB/(1/tan a) -(1/tanb)
Donc si qqn peut m'aider ça serait sympa ^^
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