factoriser [tex] \frac{ \frac{2}{6+h} - \frac{1}{3} }{h} [/tex] SVP.... Pergunta de ideia delila98

June 2021 1 73 Report

factoriser [tex] \frac{ \frac{2}{6+h} - \frac{1}{3} }{h} [/tex] SVP

Lista de comentários

Cxrly $\frac{ \frac{2}{6+h} - \frac{1}{3} }{h}$
Tu met au même dénominateur :

= $\frac{ \frac{2(3)}{3(6+h)} - \frac{1(6+h)}{3(6+h)} }{h}$

= $\frac{ \frac{6}{18+3h} - \frac{6+h}{18+3h} }{h}$

= $\frac{ \frac{6-6-h}{18+3h} }{h}$

= $\frac{ \frac{-h}{18+3h} }{h}$

= $\frac{-h}{18+3h}$ x $\frac{1}{h}$

= $\frac{-1}{18+3h}$ (on a simplifier les h en haut et en bas)

Donc $\lim_{h \to \0}0$ $\frac{ \frac{2}{6+h} - \frac{1}{3} }{h}$

= $\lim_{h \to \0}0$ $\frac{-1}{18+3h}$

= $\frac{-1}{18}$

La fonction est dérivable sur R* et la dérivée est $\frac{-1}{18}$

1 votes Thanks 1

lila98 Merciiii beaucoup pour votre aide !!

More Questions From This User See All

lila98 June 2021 | 0 Respostas

lila98 June 2021 | 0 Respostas

lila98 June 2021 | 0 Respostas

lila98 June 2021 | 0 Respostas

lila98 June 2021 | 0 Respostas

lila98 June 2021 | 0 Respostas

lila98 June 2021 | 0 Respostas

lila98 June 2021 | 0 Respostas

lila98 June 2021 | 0 Respostas

lila98 June 2021 | 0 Respostas

Helpful Links

Política de Privacidade

Termos e Condições

direito autoral

Helpful Social

Copyright © 2024 ELIBRARY.TIPS - All rights reserved.