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Anais30630
@Anais30630
April 2019
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Trouver trois entiers consécutifs dont la somme est égale à 2013.
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winner123
Verified answer
Bonsoir
tu notes n le nombre cherché
n + n + 1 + n + 2 = 2 013
3 n = 2 013 - 3
3 n = 2 010
n = 670
670, 671 et 672
2 votes
Thanks 5
rmillet
2013/3= à peu près 670 donc 670+671+672
1 votes
Thanks 4
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Verified answer
Bonsoirtu notes n le nombre cherché
n + n + 1 + n + 2 = 2 013
3 n = 2 013 - 3
3 n = 2 010
n = 670
670, 671 et 672