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Elyaakoubi
@Elyaakoubi
May 2019
1
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Salut j'ai besoin d'aide SOS svp aidez moi
ON A : ABC UN TRIANGLE S sa surface
demontrez que
S=1/2 bc Sin A=1/2 ab SinB= 1/2 ac Sin B
avec: c=AB
a=BC
b=AC
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ProfdeMaths1
Verified answer
Soit ABC un triangle
AB=c ; AC=b ; BC=a
soit h la hauteur issue de B
donc S=1/2*h*b
or sin(C)=h/a donc S=1/2*ab*sin(C)
de meme : S=1/2*ac*sin(B)=1/2*bc*sin(A)
on appelle cela la
Formule des SINUS
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Verified answer
Soit ABC un triangleAB=c ; AC=b ; BC=a
soit h la hauteur issue de B
donc S=1/2*h*b
or sin(C)=h/a donc S=1/2*ab*sin(C)
de meme : S=1/2*ac*sin(B)=1/2*bc*sin(A)
on appelle cela la Formule des SINUS