Bonjours, calculer les solutions suivantes :
A) y=2/3x+3 y=3x-4
B) y=2/3x+3 y=-1/2x+3
Besoin d'aiide urgence :)
des systèmes...
A)y=(2/3)x+3
y=3x-4
==> (2/3)x+3=3x-4
(2/3)x-3x=-4-3=-7
(-7/3)x=-7
x=7/(7/3)=7*(3/7)=3
et y=3*3-4=5
le couple solution (3;5)
B) y=2/3x+3y=-1/2x+3
(2/3)x+3=(-1/2)x+3
(2/3)x+(1/2)x=0
x=0
y=3
couple solution (0;3)
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des systèmes...
A)y=(2/3)x+3
y=3x-4
==> (2/3)x+3=3x-4
(2/3)x-3x=-4-3=-7
(-7/3)x=-7
x=7/(7/3)=7*(3/7)=3
et y=3*3-4=5
le couple solution (3;5)
B) y=2/3x+3
y=-1/2x+3
(2/3)x+3=(-1/2)x+3
(2/3)x+(1/2)x=0
x=0
y=3
couple solution (0;3)