(2x - 5) × (x - 4) - 7 = (x - 2) × (x - 3)

[tex] \\ 2x {}^{2} - 8x - 5x + 20 - 7 = (x - 2) \times (x - 3) \\ \\ [/tex]

[tex]2x {}^{2} - 8x - 5x + 20 - 7 = x {}^{2} - 3x - 2x + 6 [/tex]

[tex]2x {}^{2} - 13x + 20 - 7 = x {}^{2} - 3x - 2x + 6[/tex]

[tex]2x {}^{2} - 13x + 13 = x {}^{2} - 3x - 2x + 6[/tex]

[tex]2x {}^{2} - 13x + 13 = x {}^{2} - 5x + 6[/tex]

[tex]2x {}^{2} - 13x + 13 - x {}^{2} + 5x - 6 = 0[/tex]

[tex]x {}^{2} - 13x + 13 + 5x - 6 = 0[/tex]

[tex]x {}^{2} - 8x + 13 - 6 = 0[/tex]

[tex]x {}^{2} - 8x + 7 = 0[/tex]

[tex]x {}^{2} - x - 7x + 7 = 0[/tex]

[tex]x \times (x - 1) - 7x + 7 = 0[/tex]

[tex]x \times (x - 1) - 7(x - 1) = 0[/tex]

[tex](x - 1) \times (x - 7) = 0[/tex]

[tex]x - 1 = 0 \\ x - 7 = 0[/tex]

[tex]x = 1 \\ x = 7[/tex]

Resposta ⬇️

[tex] = > x_{1} = 1 \\ = > x_{2} = 7[/tex]

[tex]Espero \: ter \: ajudado[/tex]