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miquesiakerollaynea0
@miquesiakerollaynea0
July 2023
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4) Sendo x = (2²), y = 2²³ e z = 2³², o valor de xyz é:
Passa passa por favor
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raphaelthales02
2² . 2²³ . 2³² = 2^2+23+32 = 2⁵⁷
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miquesiakerollaynea0
Obrigada
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2² . 2²³ . 2³² = 2^2+23+32 = 2⁵⁷
✅2⁵⁷