Resposta:
n²-3n=-2
n²-3n+2=0
n'=[3+√(9-8)]/2=(3+1)/2=2
n''=[3-√(9-8)]/2=(3-1)/2=1
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Resposta:
n²-3n=-2
n²-3n+2=0
n'=[3+√(9-8)]/2=(3+1)/2=2
n''=[3-√(9-8)]/2=(3-1)/2=1
n = 2 ou n =1