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[tex] > \: resolucao \\ \\ \geqslant \: juros \: \: simples \\ \\c = 18.000.00 \\ i = 2\%a.m = \frac{2}{100} = 0.02\%a.m \\ \\ a \: \: ) \: \: 10 \: \: meses \\ \\ \\ m = c(1 + i \times t) \\ m = 18000(1 + 0.02 \times 10) \\ m = 18000(1 + 0.2) \\ m = 18000 \times 1.2 \\ m = 21600 \\ \\ resposta \: \: > \: \: 21.600.00 \\ \\ = = = = = = = = = = = = = = = = = = \\ \\ \\ b \: \: ) \: \: 1 \: ano \: e \: meio \: = \: 14 \: \: meses \\ \\ \\ m = c(1 + i \times t) \\ m = 18000(1 + 0.02 \times 14) \\ m = 18000(1 + 0.28) \\ m = 18000 \times 1.28 \\ m = 23040 \\ \\ resposta \: \: > \: \: 23.040.00 \\ \\ \\ = = = = = = = = = = = = = = = = = = \\ \\ \\ \geqslant \: juros \: \: compostos \\ \\ c = 40.000.00 \\ i = 1.2\%a.m = \frac{1.2}{100} = 0.012\%a.m \\ \\ a \: \: ) \: 2 \: semestres \: = \: 12 \: meses \\ \\ \\ m = c(1 + i) {}^{t} \\ m = 40000(1 + 0.012) {}^{12} \\ m = 40000(1.012) {}^{12} \\ m = 40000 \times 1.153894 \\ m = 46155.76 \\ \\ resposta \: \: > \: \: 46.155.76 \\ \\ = = = = = = = = = = = = = = = \\ \\ \\ b \: \: ) \: \: 5 \: trimestres \: = \: 15 \: meses \\ \\ \\ m = c(1 + i) {}^{t} \\ m = 40000(1 + 0.012)) {}^{15} \\ m = 40000(1.012) {}^{15} \\ m = 40000 \times 1.195935 \\ m = 47837.40 \\ \\ \\ resposta \: \: > \: \: 47.837.40 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant