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Math1404
@Math1404
May 2019
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Bonjour, classe de 2nde pouvez-vous factoriser
(x+3)(4x-8)-(2x+6)(x+6)
merci d'avance.
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ProfdeMaths1
Verified answer
(x+3)(4x-8)-(2x+6)(x+6)
=4(x+3)(x-2)-2(x+3)(x+6)
=(x+3)(4(x-2)-2(x+6))
=(x+3)(2x-20)
=2(x+3)(x-10)
1 votes
Thanks 1
Math1404
merci beaucoup
inequation
Verified answer
Bonsoir
(x+3)(4x-8)-(2x+6)(x+6)
4(x+3)(x-2)-2(x+3)(x+6)
(x+3)[4(x-2)-2(x+6)]
(x+3)(4x-8-2x-12)
(x+3)(2x-20)
1 votes
Thanks 1
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Verified answer
(x+3)(4x-8)-(2x+6)(x+6)=4(x+3)(x-2)-2(x+3)(x+6)
=(x+3)(4(x-2)-2(x+6))
=(x+3)(2x-20)
=2(x+3)(x-10)
Verified answer
Bonsoir(x+3)(4x-8)-(2x+6)(x+6)
4(x+3)(x-2)-2(x+3)(x+6)
(x+3)[4(x-2)-2(x+6)]
(x+3)(4x-8-2x-12)
(x+3)(2x-20)