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Berrry
@Berrry
May 2019
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Bonjour, j'ai besoin de votre aide pour cet exercice de trigonométrie de première S. J'ai réussi Les deux priemiers seulement. Merci d'avance! :)
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scoladan
Verified answer
Bonjour,
3) cos(x - π/3) = √3/2
⇔ cos(x - π/3) = cos(π/6)
⇒ x - π/3 = π/6 + k2π (k∈Z)
ou x - π/3 = -π/6 + k2π
⇔ x = π/6 + π/3 + k2π
ou x = -π/6 + π/3 + k2π
⇔ x = π/2 + k2π ou x = π/6 + k2π
4) sin(x + π/4) = 0
⇒ x + π/4 = 0 + kπ
⇔ x = -π/4 + kπ
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Verified answer
Bonjour,3) cos(x - π/3) = √3/2
⇔ cos(x - π/3) = cos(π/6)
⇒ x - π/3 = π/6 + k2π (k∈Z)
ou x - π/3 = -π/6 + k2π
⇔ x = π/6 + π/3 + k2π
ou x = -π/6 + π/3 + k2π
⇔ x = π/2 + k2π ou x = π/6 + k2π
4) sin(x + π/4) = 0
⇒ x + π/4 = 0 + kπ
⇔ x = -π/4 + kπ