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manelnihel
@manelnihel
January 2021
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Bonjour, j’aimerai savoir si l’exo 3 est bon et si vous pouvez m’expliquer comment faire le 4?
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Geijutsu
Verified answer
Bonsoir,
5π/4 ≡ 3π/4 [2π]
D'où cos(5π/4) = cos(3π/4) = -(√2)/2
14π/3 ≡ 2π/3 [2π]
D'où tan(14π/3) = tan(2π/3) = sin(2π/3)/cos(2π/3) = ((√3)/2)/(-1/2) = -√3
-43π/6 ≡ 5π/6 [2π]
D'où sin(-43π/6) = sin(5π/6) = 1/2
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Thanks 1
manelnihel
Pour le premier j’ai trouvé -racine de deux sur deux
Et le troisième j’ai trouvé 1/2
Je sais pas si c’est bon
Geijutsu
Alors pardon oui pour la 3 je me corrige tu as eu juste.
Geijutsu
Comme quoi tu vois tout le monde peut faire des erreurs
Geijutsu
Pour la 1 aussi tu avais raison au fait
Geijutsu
J'avais fait trop vigte
manelnihel
Haha merci bcp ;)
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Verified answer
Bonsoir,5π/4 ≡ 3π/4 [2π]
D'où cos(5π/4) = cos(3π/4) = -(√2)/2
14π/3 ≡ 2π/3 [2π]
D'où tan(14π/3) = tan(2π/3) = sin(2π/3)/cos(2π/3) = ((√3)/2)/(-1/2) = -√3
-43π/6 ≡ 5π/6 [2π]
D'où sin(-43π/6) = sin(5π/6) = 1/2
Et le troisième j’ai trouvé 1/2
Je sais pas si c’est bon