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Manelnihel
@Manelnihel
May 2019
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Bonjour, je n’arrive pas à calculer ces intégrales
Merci beaucoup
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laurance
D'après l'énoncé on sait que F(2) - F(1)= 3 F(5)-F(1) =2 et G(5)-G(1)=1
la première intégrale = G(5) - G(5)=0
la deuxieme = 1/5 ( F(5) + G(5) - F(1) - G(1)=
= 1/5(F(5)-F(1) ) +1/5(G(5)-G(1) ) = 1/ 5 * 2 +1/5* 1 = 3/5
la troisieme = 4( F(1) - F(2) ) = 4( -3)= -12
la quatrieme = 3( F(5) -F(1) ) - 2(G(5) -G(1) ) = 3*2-2*1 = 4
la cinquieme= F(5) - F(2)= F(5) - F(1) + F(1) - F(2)= 2 + (-3)= -1
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la première intégrale = G(5) - G(5)=0
la deuxieme = 1/5 ( F(5) + G(5) - F(1) - G(1)=
= 1/5(F(5)-F(1) ) +1/5(G(5)-G(1) ) = 1/ 5 * 2 +1/5* 1 = 3/5
la troisieme = 4( F(1) - F(2) ) = 4( -3)= -12
la quatrieme = 3( F(5) -F(1) ) - 2(G(5) -G(1) ) = 3*2-2*1 = 4
la cinquieme= F(5) - F(2)= F(5) - F(1) + F(1) - F(2)= 2 + (-3)= -1