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Magie78
@Magie78
May 2019
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Bonjour j’aurais besoin d’aide pour l’exercice 68 svp c’est niveau 3eme.
Merci d’avance
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Bonjour,
1) f(x₁) = ax₁+b
f(x₂) = ax₂+b
donc f(x₁) - f(x₂) = (ax₁+b) - (ax₂+b)
= ax₁ + b - ax₂ - b
= ax₁ - ax₂
2) ax₁ - ax₂ = a(x₁-x₂)
3) (f(x₂) - f(x₁)) / (x₂-x₁) = (ax₂ - ax₁) / (x₂-x₁)
= (a(x₂-x₁)) / (x₂-x₁)
= a
4) On vient de démontrer que, pour une fonction affine (f(x)=ax+b), les
accroissements de f(x) sont proportionnels aux accroissements de x
Le calcul (f(x₂) - f(x₁)) / (x₂-x₁) est le taux d'accroissement
1 votes
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1) f(x₁) = ax₁+b
f(x₂) = ax₂+b
donc f(x₁) - f(x₂) = (ax₁+b) - (ax₂+b)
= ax₁ + b - ax₂ - b
= ax₁ - ax₂
2) ax₁ - ax₂ = a(x₁-x₂)
3) (f(x₂) - f(x₁)) / (x₂-x₁) = (ax₂ - ax₁) / (x₂-x₁)
= (a(x₂-x₁)) / (x₂-x₁)
= a
4) On vient de démontrer que, pour une fonction affine (f(x)=ax+b), les
accroissements de f(x) sont proportionnels aux accroissements de x
Le calcul (f(x₂) - f(x₁)) / (x₂-x₁) est le taux d'accroissement