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Moussaillon5946
@Moussaillon5946
May 2019
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Bonjour
Je dois démontrer
cotg²x - cos²x = cotg²x .cos²x
Pouvez-vous m'aider
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ProfdeMaths1
Verified answer
cotg²x - cos²x
=1/(tan²(x))-cos²(x)
=cos²(x)/sin²(x)-cos²(x)
=(cos²(x)-cos²(x).sin²(x))/sin²(x)
=(cos²(x))(1-sin²(x))/sin²(x)
=(cos²(x)).(cos²(x))/sin²(x)
=cos²(x)/tan²(x)
=
cotg²x .cos²x
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Verified answer
cotg²x - cos²x=1/(tan²(x))-cos²(x)
=cos²(x)/sin²(x)-cos²(x)
=(cos²(x)-cos²(x).sin²(x))/sin²(x)
=(cos²(x))(1-sin²(x))/sin²(x)
=(cos²(x)).(cos²(x))/sin²(x)
=cos²(x)/tan²(x)
= cotg²x .cos²x