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MzelleCelia
@MzelleCelia
May 2019
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Bonjour, je suis une catastrophe en maths, quelqu'un pour m'aider? :)
B(x) = (1,2x) - (0,2x au carré - 0,4x + 1)
Merci !
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Commentaires (5)
Que faut-il faire ? Développer et réduire ?
B(x) = (1,2x) - (0,2x² - 0,4x + 1)
= 1,2x - 0,2x² + 0,4x - 1
= 0,2x² + 1,2x + 0,4x - 1
= 0,2x² + 1,6x - 1
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MzelleCelia
Merci !
nadiab
B(x) est déjà développer, il suffit de réduire.
Donc, on obtiens:
B(x) = (1,2x)-(0,2x²-0,4x+1)
B(x) = 1,2x-0,2x²+0,4x-1
B(x) = -0,2x²+1,6x-1
1 votes
Thanks 0
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B(x) = (1,2x) - (0,2x² - 0,4x + 1)
= 1,2x - 0,2x² + 0,4x - 1
= 0,2x² + 1,2x + 0,4x - 1
= 0,2x² + 1,6x - 1
Donc, on obtiens:
B(x) = (1,2x)-(0,2x²-0,4x+1)
B(x) = 1,2x-0,2x²+0,4x-1
B(x) = -0,2x²+1,6x-1