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Maleewan
@Maleewan
May 2019
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Bonjour pouvez vous m'aider sur mon exercice de trigonométrie merci d'avance l exercice est au dessous
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taalbabachir
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Tan 37° = SO/SL ⇒ SO = SL x tan37° = 6 x 0.75355 = 4.521 cm on arrondi au dixième donc SO = 4.5 cm
cos 58° = OL/SO ⇒ SO = OL/tan 58° = 3/1.6 = 1.875 cm on arrondi au dixième donc SO = 1.9 cm
on cherche l'angle OIS = 180 - ( 90 + 29) = 180 - 119 = 61°
tan OIS = SO/OI ⇒ SO = OI x tan OIS = 4 x tan 61° = 4 x 1.8 = 7.216 cm
on arrondi au dixième donc SO = 7.2 cm
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Tan 37° = SO/SL ⇒ SO = SL x tan37° = 6 x 0.75355 = 4.521 cm on arrondi au dixième donc SO = 4.5 cmcos 58° = OL/SO ⇒ SO = OL/tan 58° = 3/1.6 = 1.875 cm on arrondi au dixième donc SO = 1.9 cm
on cherche l'angle OIS = 180 - ( 90 + 29) = 180 - 119 = 61°
tan OIS = SO/OI ⇒ SO = OI x tan OIS = 4 x tan 61° = 4 x 1.8 = 7.216 cm
on arrondi au dixième donc SO = 7.2 cm