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Math1404
@Math1404
May 2019
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Bonjour question 2,3 et 4 de l'exercice 4 s'il vous plaît
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ProfdeMaths1
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Ex 4:
2) aire grisée=(4-2x)(3-2x)
aire blanche=12-(4-2x)(3-2x)
⇒ (4-2x)(3-2x)=12-(4-2x)(3-2x)
⇒ 2(4x²-14x+12)-12=0
⇒ 8x²-28x+12=0
3) 2(2x-3,5)²-12,5=2(4x²-14x+12,25)-12,5
=8x²-28x+24,5-12,5
=8x²-28x+12
4) on cherche x tel que : 2(2x-3,5)²-12,5=0
⇒(2x-3,5)²-6,25=0
⇒(2x-3,5)²-2,5²=0
⇒(2x-3,5-2,5)(2x-3,5+2,5)=0
⇒(2x-6)(2x-1)=0
⇒x=3 ou x=1/2
or la valeur est incohérente ⇒ x=1/2
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Verified answer
Ex 4:2) aire grisée=(4-2x)(3-2x)
aire blanche=12-(4-2x)(3-2x)
⇒ (4-2x)(3-2x)=12-(4-2x)(3-2x)
⇒ 2(4x²-14x+12)-12=0
⇒ 8x²-28x+12=0
3) 2(2x-3,5)²-12,5=2(4x²-14x+12,25)-12,5
=8x²-28x+24,5-12,5
=8x²-28x+12
4) on cherche x tel que : 2(2x-3,5)²-12,5=0
⇒(2x-3,5)²-6,25=0
⇒(2x-3,5)²-2,5²=0
⇒(2x-3,5-2,5)(2x-3,5+2,5)=0
⇒(2x-6)(2x-1)=0
⇒x=3 ou x=1/2
or la valeur est incohérente ⇒ x=1/2