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Adrianaconcurseira
@Adrianaconcurseira
May 2020
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Calcule três números x, y, z, diretamente proporcionais a 2, 3 e 4, sabendo-se que: 3x - y + 2z = 66.
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Heberwagner
- x, y, z, diretamente proporcionais a 2, 3 e 4 => x/2=y/3=z/4
x/2 = z/4 => x = z/2 // y/3 = z/4 => y = 3z/4
- para 3x - y + 2z = 66, obtemos:
3(z/2) - 3z/4 + 2z = 66 => 3z/2 - 3z/4 + 2z = 66 => mmc (2,4) = 4
6z/4 - 3z/4 + 8z = 66 => 6z - 3z + 8z = 66.4 => 11z = 264 =>
z = 24
x = z/2 => x = 24/2 =>
x = 12
// y = 3z/4 => y = 3.24/4 =>
y = 18
2 votes
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x/2 = z/4 => x = z/2 // y/3 = z/4 => y = 3z/4
- para 3x - y + 2z = 66, obtemos:
3(z/2) - 3z/4 + 2z = 66 => 3z/2 - 3z/4 + 2z = 66 => mmc (2,4) = 4
6z/4 - 3z/4 + 8z = 66 => 6z - 3z + 8z = 66.4 => 11z = 264 => z = 24
x = z/2 => x = 24/2 => x = 12 // y = 3z/4 => y = 3.24/4 => y = 18