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Kikakika1996
@Kikakika1996
April 2019
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Comment doit-on demontrer celá :
|x+y| < |x|+|y|
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MichaelS
Verified answer
On différencie deux cas :
Cas 1 : x + y > 0
|x + y| = x + y
|x + y| < |x| + |y| ⇔ x + y < |x| + |y|
Cas 2 : x + y < 0
|x + y| = - (x + y) = -x - y
|x + y| < |x| + |y| ⇔ - x - y < |x| + |y|
Pour tout x on a bien |x + y| < |x| + |y|
1 votes
Thanks 0
MichaelS
j'ai remplacé |x + y| par x + y ...
MichaelS
je peux plus modifier ma réponse :/ merci de cette précision ;)
More Questions From This User
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kikakika1996
June 2021 | 0 Respostas
aidez moi svp... merci d'avance ;)
Responda
Kikakika1996
April 2019 | 0 Respostas
slt a tous je veux la demonsstttration de ceeettttte valeur absolue merci d'avancccce ||x|-|y|| < |x-y|
Responda
Kikakika1996
April 2019 | 0 Respostas
Je veux cette demonstration : si la valeur absolue de x : |x|< a ---> -a < x < a
Responda
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Lista de comentários
Verified answer
On différencie deux cas :Cas 1 : x + y > 0
|x + y| = x + y
|x + y| < |x| + |y| ⇔ x + y < |x| + |y|
Cas 2 : x + y < 0
|x + y| = - (x + y) = -x - y
|x + y| < |x| + |y| ⇔ - x - y < |x| + |y|
Pour tout x on a bien |x + y| < |x| + |y|