Resposta:
a4= 35
Explicação passo a passo:
[tex] > \: resolucao \\ \\ \geqslant \: progressao \: \: aritmetica \\ \\ an = a1 + (n - 1)r \\ 83 = 23 + (16 - 1)r \\ 83 = 23 + 15r \\ 83 - 23 = 15r \\ 60 = 15r \\ r = \frac{60}{15} \\ r = 4 \\ \\ = = = = = = = = = = = = = = = = = \\ \\ \\ > \: o \: quarto \: termo \: da \: pa \\ \\ an = a1 + (n - 1)r \\ an = 23 + (4 - 1)4 \\ an = 23 + 3 \times 4 \\ an = 23 + 12 \\ an = 35 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant [/tex]
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Resposta:
a4= 35
Explicação passo a passo:
[tex] > \: resolucao \\ \\ \geqslant \: progressao \: \: aritmetica \\ \\ an = a1 + (n - 1)r \\ 83 = 23 + (16 - 1)r \\ 83 = 23 + 15r \\ 83 - 23 = 15r \\ 60 = 15r \\ r = \frac{60}{15} \\ r = 4 \\ \\ = = = = = = = = = = = = = = = = = \\ \\ \\ > \: o \: quarto \: termo \: da \: pa \\ \\ an = a1 + (n - 1)r \\ an = 23 + (4 - 1)4 \\ an = 23 + 3 \times 4 \\ an = 23 + 12 \\ an = 35 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant [/tex]