An = 77
Explicação passo-a-passo:
An = a1 + (n - 1) * r
An32 = -16 + (32 - 1)*(3)
An32 = -16 + 31 * (3)
An32 = -16 + (93)
[tex] > \: resolucao \\ \\ \geqslant \: progressao \: \: aritmetica \\ \\ an = a1 + (n - 1)r \\ 32 = - 16 + (n - 1)3 \\ 32 = - 16 + 3n - 3 \\ 32 = - 19 + 3n \\ 32 + 19 = 3n \\ 51 = 3n \\ n = \frac{51}{3} \\ n = 17 \\ \\ \\ resposta \: > \: 32 \: e \: o \: decimo \: setimo \: \\ termo \: da \: pa \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant \geqslant [/tex]
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An = 77
Explicação passo-a-passo:
An = a1 + (n - 1) * r
An32 = -16 + (32 - 1)*(3)
An32 = -16 + 31 * (3)
An32 = -16 + (93)
An = 77
[tex] > \: resolucao \\ \\ \geqslant \: progressao \: \: aritmetica \\ \\ an = a1 + (n - 1)r \\ 32 = - 16 + (n - 1)3 \\ 32 = - 16 + 3n - 3 \\ 32 = - 19 + 3n \\ 32 + 19 = 3n \\ 51 = 3n \\ n = \frac{51}{3} \\ n = 17 \\ \\ \\ resposta \: > \: 32 \: e \: o \: decimo \: setimo \: \\ termo \: da \: pa \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant \geqslant [/tex]