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sila51
@sila51
June 2021
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Développer chaque expression en utilisant l'identités remarquable;
a)(x+3)²
b)(x+6)²
c)(3x+2)²
d(1+5a)²
e)(x-4)²
f)(x-5)²
g)(x-5)²
h)(5x-1
i)(10-3x)²
j)(7-x)(7+x)
k)(1-y)(1+y)
L)(1-3x)(1+3x)
m)(5b+2)(5b-2)
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fandejen
A/ x²+2×x×3+3² = x²+6x+9
b/x²+2×x×6+6² = x²+12x+36
c/(3x)²+2×3x×2+2² = 9x²+12x+4
d/1²+2×1×5a+(5a)² = 1+10a+25a²
e/x²-2×x×4+4² = x²-8x+16
f/ x²-2×x×5+5² = x²-10x+25
g/ x²-2×x×5+5² = x²-10x+25
h/ (5x)²-2×5x×1+1² = 25x²-10x+1
i/ 10²-2×10×3x+(3x)² = 100-60x+9x²
j/7²-x² = 49-x²
k/ 1²-y² = 1-y²
l/1²-(3x)² = 1 - 9x²
m/ (5b)² - 2² = 25b² - 4
0 votes
Thanks 1
sila51
et les autres??
fandejen
c'est trop long !!
sila51
oh c trop long donc cest cas la me lai fait pas !!
fandejen
bon allez j'essaye de tous faire
sila51
ah bh mercii alors jattend
sila51
,,,,,
fandejen
dsl pour l'attente
sila51
merciii
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b/x²+2×x×6+6² = x²+12x+36
c/(3x)²+2×3x×2+2² = 9x²+12x+4
d/1²+2×1×5a+(5a)² = 1+10a+25a²
e/x²-2×x×4+4² = x²-8x+16
f/ x²-2×x×5+5² = x²-10x+25
g/ x²-2×x×5+5² = x²-10x+25
h/ (5x)²-2×5x×1+1² = 25x²-10x+1
i/ 10²-2×10×3x+(3x)² = 100-60x+9x²
j/7²-x² = 49-x²
k/ 1²-y² = 1-y²
l/1²-(3x)² = 1 - 9x²
m/ (5b)² - 2² = 25b² - 4