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Apame
@Apame
April 2019
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Développer l'expression littérale 2(x-2)(x-8) = 0.
Merci de l'aide
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cavalier
2 (x-2) (x-8)=0
2 (x² -8x -2x +16) = 0
2 ( x² -10x +16) = 0
2x²-20x +32 = 0
par conséquent est x = 2 ou x= 8
1 votes
Thanks 1
cavalier
n'hésite pas à noter meilleure réponse, erci
apame
Je ne peux pas
apame
as tu reçu mon message ?
Fafas
La solution au système est très simple : x=2 ou x=8
Développer:
2(x-2)(x-8)
= (2x-4)(x-8)
= 2x²-16x-4x+32
= 2x²-20x+32
1 votes
Thanks 0
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Lista de comentários
2 (x² -8x -2x +16) = 0
2 ( x² -10x +16) = 0
2x²-20x +32 = 0
par conséquent est x = 2 ou x= 8
Développer:
2(x-2)(x-8)
= (2x-4)(x-8)
= 2x²-16x-4x+32
= 2x²-20x+32