Bonjour, voici la solution :
On utilise la formule ()' =
f'(x) = 5*2x -
f'(x) = 5*2x +
(il faut ignorer les "à" majuscule, c'est un bug)
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Bonjour, voici la solution :
On utilise la formule (
)' = 
f'(x) = 5*2x -
f'(x) = 5*2x -
f'(x) = 5*2x +
(il faut ignorer les "à" majuscule, c'est un bug)