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Evelynelanguil
@Evelynelanguil
April 2019
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Merci d avance de m aidez?
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nathalienouts
Cos43° = AB/AC
AC = AB/cos43
AC = 99/cos43
AC = 135 m
Théorème de Pythagore
AB²+BC² = AC²
BC² = AC²-AB²
BC = √(AC²-AB²)
BC = √(135²-99²)
BC = 91,8 m
HC = BC-HB
HC = 91,8-46,2
HC = 45,6 m
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J ai de grandes difficultees pouvez vous m aidez merci a vous;
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Lista de comentários
AC = AB/cos43
AC = 99/cos43
AC = 135 m
Théorème de Pythagore
AB²+BC² = AC²
BC² = AC²-AB²
BC = √(AC²-AB²)
BC = √(135²-99²)
BC = 91,8 m
HC = BC-HB
HC = 91,8-46,2
HC = 45,6 m