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Réponse :

Bonjour

Explications étape par étape

P = 50 m

1) P = 2(L + l)

Si L = x alors on a :

50 = 2(x + l)

50/2 = x + l

l = 25 - x

2) A = 100 m^2 montrer que :

x^2 - 25x + 100 = 0

A = L * l

100 = x(25 - x)

100 = 25x - x^2

x^2 - 25x + 100 = 0

3) dimensions de la parcelle :

> 0 donc deux solutions

X1 = (25 - 15)/2 = 10/2 = 5 m

X2 = (25 + 15)/2 = 40/2 = 20 m

largeur = 5 m

Longueur = 20 m

4) x + y = S

xy = P

y = S - x

y = P/x

S - x = P/x

xS - x^2 = P

x^2 - Sx + P = 0