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MelissaMar
@MelissaMar
June 2021
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Pouvez vous m'aider a faire l'exo 2 please :)
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Li3b3
A) 1/n - 1/n+1 = on met tous sur le meme denominateur 1(n+1)/n(n+1)-1n/n(n+1) = 1n+1-1n/n(n+1) Donc 1n et -1n s'annule et on obtient 1/n(n+1)
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MelissaMar
Malheureusement je comprend pas lorsque c'est écrit comme sa :( Il faut que sa soit écrit comme sur la photo :(
Li3b3
Recopie le sur une feuille pour mieux comprendre, je peux pas faire mieux
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