Item (D).
__________________________
[tex]\large\text{$\sf\:LQ2=\dfrac{perimetro}{4}\to\:LQ2=\dfrac{32}{4}\to\boxed{LQ2=8\:cm}$\sf}[/tex]
[tex]\large\text{$\sf\:LQ1=\sqrt{4}\to\boxed{LQ1=2\:cm}$\sf}[/tex]
LQ3 = LQ2 - LQ1
LQ3 = 8 - 2
[tex]\large\text{$\sf\boxed{LQ3=6\:cm}$\sf}[/tex]
[tex]\large\text{$\sf\:AQ3=(LQ3)^{2}\to\:AQ3=6^{2}\to\boxed{AQ3=36\:cm^{2}}$\sf}[/tex]
Portanto, o item correto é o (D).
_____________________________________
Veja mais sobre o assunto em:
https://brainly.com.br/tarefa/52939891
https://brainly.com.br/tarefa/173182
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Item (D).
__________________________
[tex]\large\text{$\sf\:LQ2=\dfrac{perimetro}{4}\to\:LQ2=\dfrac{32}{4}\to\boxed{LQ2=8\:cm}$\sf}[/tex]
[tex]\large\text{$\sf\:LQ1=\sqrt{4}\to\boxed{LQ1=2\:cm}$\sf}[/tex]
LQ3 = LQ2 - LQ1
LQ3 = 8 - 2
[tex]\large\text{$\sf\boxed{LQ3=6\:cm}$\sf}[/tex]
[tex]\large\text{$\sf\:AQ3=(LQ3)^{2}\to\:AQ3=6^{2}\to\boxed{AQ3=36\:cm^{2}}$\sf}[/tex]
Portanto, o item correto é o (D).
_____________________________________
Veja mais sobre o assunto em:
https://brainly.com.br/tarefa/52939891
https://brainly.com.br/tarefa/173182