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Yumi0
@Yumi0
April 2019
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Résoudres les inéquations :
1) 2x (1- x) sur x au carré + 4 > 0
2) 2 sur x + 3 < 1
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danielwenin
Verified answer
(2×(1-×)/(×^2+4) > 0
×^2+4> 0 donc ça revient à dire 2×(1-×)> 0
0 <×<1
2) 2/(×+3) < 1 => 2/(×+3)-1 < 0 => (2-×-3)/(×+3) => (-1-×)/(×+3) < 0
× < -3 ou x > -1
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Verified answer
(2×(1-×)/(×^2+4) > 0×^2+4> 0 donc ça revient à dire 2×(1-×)> 0
0 <×<1
2) 2/(×+3) < 1 => 2/(×+3)-1 < 0 => (2-×-3)/(×+3) => (-1-×)/(×+3) < 0
× < -3 ou x > -1