A(x) = [(2 x + 1)(x - 3)]/[(2 - x)(x+1)]
x - ∞ - 1 - 1/2 2 3 + ∞
2 x + 1 - - 0 + + +
x - 3 - - - - 0 +
2 - x + + + || - -
x+1 - || + + + +
A(x) - || + 0 - || + 0 -
B(x) = 2 x - 5 x² = x(2 - 5 x)
x - ∞ 0 2/5 + ∞
x - 0 + +
2 - 5 x + + 0 -
B(x) - + -
vous faite le reste
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A(x) = [(2 x + 1)(x - 3)]/[(2 - x)(x+1)]
x - ∞ - 1 - 1/2 2 3 + ∞
2 x + 1 - - 0 + + +
x - 3 - - - - 0 +
2 - x + + + || - -
x+1 - || + + + +
A(x) - || + 0 - || + 0 -
B(x) = 2 x - 5 x² = x(2 - 5 x)
x - ∞ 0 2/5 + ∞
x - 0 + +
2 - 5 x + + 0 -
B(x) - + -
vous faite le reste