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Itielteixeira
@Itielteixeira
December 2019
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1) Aplicando a regra do quadrado da diferença de dois termos. (a-b)²=a²-2ab+b².
A) (3a-b)²
B) (xy-5)²
C) (x-4)²
D) (a²-xy)²
E) (r-s)²
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emicosonia
1) Aplicando a regra do quadrado da diferença de dois termos.
(a-b)²=a²-2ab+b².
A) (3a-b)²
(3a - b)(3a - b) =
9a² - 3ab - 3ab + b²
9a² - 6ab + b²
assim
(3a - b)² = 9a² - 6ab + b²
B) (xy-5)²
(xy - 5)(xy - 5) =
x²y² - 5xy - 5xy + 25
x²y² - 10xy + 25
assim
(xy - 5)² = x²y² - 10xy + 25
C) (x-4)²
(x - 4)(x- 4) =
x² - 4x - 4x + 16
x² - 8x + 16
assim
(x - 4)² = x² - 8x + 16
D) (a²-xy)²
(a² - xy)(a² -xy) =
a
⁴ - a²xy - a²xy + x²y²
a
⁴ - 2a²xy + x²y²
assim
(a² -xy)² = a
⁴ - 2a²xy + x²y²
E) (r-s)²
(r - s)(r - s) =
r² - rs - rs + s²
r² - 2rs + s²
assim
(r - s)² = r² - 2rs + s²
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(a-b)²=a²-2ab+b².
A) (3a-b)²
(3a - b)(3a - b) =
9a² - 3ab - 3ab + b²
9a² - 6ab + b²
assim
(3a - b)² = 9a² - 6ab + b²
B) (xy-5)²
(xy - 5)(xy - 5) =
x²y² - 5xy - 5xy + 25
x²y² - 10xy + 25
assim
(xy - 5)² = x²y² - 10xy + 25
C) (x-4)²
(x - 4)(x- 4) =
x² - 4x - 4x + 16
x² - 8x + 16
assim
(x - 4)² = x² - 8x + 16
D) (a²-xy)²
(a² - xy)(a² -xy) =
a⁴ - a²xy - a²xy + x²y²
a⁴ - 2a²xy + x²y²
assim
(a² -xy)² = a⁴ - 2a²xy + x²y²
E) (r-s)²
(r - s)(r - s) =
r² - rs - rs + s²
r² - 2rs + s²
assim
(r - s)² = r² - 2rs + s²