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Filomena171
@Filomena171
August 2019
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1. Calcule quantos elementos tem essas P.G
a.) a1=9 , an=3 elevado a 20 e q=3
b.) an=1875 , a1=3 e q= 5.
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emicosonia
1. Calcule quantos elementos tem essas P.G
n = elementos
a.) a1=9 , an=3 elevado a 20 e q=3
DEIXAR bases IGUAIS
FÓRMULA da PG
an = a1.q^(n - 1)
3²º = 9.3^(n - 1) ( lembrando que 9 = 3x3 = 3²)
3²º = 3².3^(n - 1) mesmo que
3².3^(n - 1) = 3²º
3²º
3^(n - 1) = ----------
3²
3²(3¹
⁸)
3^(n - 1) = ---------- elimina AMBOS (3²)
3²(1)
3¹
⁸
3^(n- 1) = -------
1
3^(n - 1) = 3
¹⁸ mesma BASE (3))
(n - 1) = 18
n - 1 = 18
n = 18 + 1
n = 19 ( elementos)
b.) an=1875 , a1=3 e q= 5.
an = a1.q^(n - 1)
1875 = 3.5^(n - 1) mesmo que
3.5^(n - 1) = 1875
5^(n- 1) = 1875/3
5^(n - 1)= 625 ( 625 = 5x5x5x5 = 5
⁴)
5^(n - 1) = 5
⁴ (mesma BASE)(5))
(n - 1) = 4
n - 1 = 4
n = 4 + 1
n = 5 ( elementos)
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n = elementos
a.) a1=9 , an=3 elevado a 20 e q=3
DEIXAR bases IGUAIS
FÓRMULA da PG
an = a1.q^(n - 1)
3²º = 9.3^(n - 1) ( lembrando que 9 = 3x3 = 3²)
3²º = 3².3^(n - 1) mesmo que
3².3^(n - 1) = 3²º
3²º
3^(n - 1) = ----------
3²
3²(3¹⁸)
3^(n - 1) = ---------- elimina AMBOS (3²)
3²(1)
3¹⁸
3^(n- 1) = -------
1
3^(n - 1) = 3¹⁸ mesma BASE (3))
(n - 1) = 18
n - 1 = 18
n = 18 + 1
n = 19 ( elementos)
b.) an=1875 , a1=3 e q= 5.
an = a1.q^(n - 1)
1875 = 3.5^(n - 1) mesmo que
3.5^(n - 1) = 1875
5^(n- 1) = 1875/3
5^(n - 1)= 625 ( 625 = 5x5x5x5 = 5⁴)
5^(n - 1) = 5⁴ (mesma BASE)(5))
(n - 1) = 4
n - 1 = 4
n = 4 + 1
n = 5 ( elementos)