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BrunoUchoa
@BrunoUchoa
November 2019
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10²=(R+2)²+R²
100=(R+2)²+R²
e depois ?
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decioignacio
100 = R² + 4R + 4 + R²
2R² + 4R - 96 = 0
R² + 2R - 48 = 0
(R + 8)(R - 6) = 0
R + 8 = 0 ⇒ R' = -8
R - 6 = 0 ⇒ R'' = 6
2 votes
Thanks 1
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Lista de comentários
2R² + 4R - 96 = 0
R² + 2R - 48 = 0
(R + 8)(R - 6) = 0
R + 8 = 0 ⇒ R' = -8
R - 6 = 0 ⇒ R'' = 6