Articles
Register
Sign In
Search
Nahraa
@Nahraa
December 2019
1
82
Report
Gente dar uma força que eu esqueci?
a)(1/8)^x=128
b)1/125=625^x
c) 8^x-9=16^x/2
d)0,2^x=(1/125)^x-6
e)7^x=343
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
exalunosp
A
(1/8)ˣ = 128 = 2⁷
[( 1/2)³ ]ˣ = 2⁷
( 1/2)³ˣ = ( 2 )⁻⁷
( 1/2)³ˣ = ( 1/2)⁷
3x = 7
x = 7/3 ***
b
( 1/125) = 625ˣ
( 1/5)³ =[(1/5)⁴]ˣ
( 1/5)³ = ( 1/5)⁴ˣ
4x = 3
x = 3/4 ****
c
(8)ˣ⁻⁹ = ( 16)ˣ/²
(2³)ˣ⁻⁹ =( 2⁴ )ˣ/²
Notas :
3 . ( x - 9 = 3x - 27
4/1 * x/2 = 4x/2 = 2x
( 2 )³ˣ⁻²⁷ = ( 2 )²ˣ
3x - 27 = 2x
3x - 2x = 27
x = 27 ***
d
( 2/10)ˣ = ( 1/125)ˣ⁻⁶
( 1/5)ˣ = [(1/5)³]ˣ⁻⁶
Nota : 3 * ( x - 6) = 3x - 18 **
( 1/5)ˣ = ( 1/5)³ˣ⁻¹⁸
x = 3x - 18
x - 3x = -18
-2x = - 18
2x = 18
x = 18/2 = 9 ***
e
7ˣ = 343
7ˣ = 7³
x = 3 ***
1 votes
Thanks 0
More Questions From This User
See All
Nahraa
December 2019 | 0 Respostas
Responda
Recomendar perguntas
Deividyfreitas
May 2020 | 0 Respostas
BlackShot
May 2020 | 0 Respostas
Vanessakellen
May 2020 | 0 Respostas
Guiduarter
May 2020 | 0 Respostas
Mrzaine
May 2020 | 0 Respostas
O QUE SERIA AUTONOMIA?
Grazifer
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
a palavra rapidez formou se de qual derivacao
Celiana
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
Anatercia
May 2020 | 0 Respostas
×
Report "Gente dar uma força que eu esqueci? a)(1/8)^x=128 b)1/125=625^x c) 8^x-9=16^x/2 d)0,2^x=(1/125)^x-6.... Pergunta de ideia de Nahraa"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
(1/8)ˣ = 128 = 2⁷
[( 1/2)³ ]ˣ = 2⁷
( 1/2)³ˣ = ( 2 )⁻⁷
( 1/2)³ˣ = ( 1/2)⁷
3x = 7
x = 7/3 ***
b
( 1/125) = 625ˣ
( 1/5)³ =[(1/5)⁴]ˣ
( 1/5)³ = ( 1/5)⁴ˣ
4x = 3
x = 3/4 ****
c
(8)ˣ⁻⁹ = ( 16)ˣ/²
(2³)ˣ⁻⁹ =( 2⁴ )ˣ/²
Notas :
3 . ( x - 9 = 3x - 27
4/1 * x/2 = 4x/2 = 2x
( 2 )³ˣ⁻²⁷ = ( 2 )²ˣ
3x - 27 = 2x
3x - 2x = 27
x = 27 ***
d
( 2/10)ˣ = ( 1/125)ˣ⁻⁶
( 1/5)ˣ = [(1/5)³]ˣ⁻⁶
Nota : 3 * ( x - 6) = 3x - 18 **
( 1/5)ˣ = ( 1/5)³ˣ⁻¹⁸
x = 3x - 18
x - 3x = -18
-2x = - 18
2x = 18
x = 18/2 = 9 ***
e
7ˣ = 343
7ˣ = 7³
x = 3 ***