Sabendo que [tex]L^{-1}[/tex] {S/S²+144}=cos(12t), aplicando a propriedade de mudança de escala, podemos concluir que [tex]L^{-1}[/tex] {6s/6s²+144} é igual a:
Escolha uma:

(a). 1/3·cos(6t)
(b). 6·cos(6t)
(c). 1/4·sen(12t)
(d). 1/6·cos(2t)
(e). 1/12·cos(12t)
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