a) x²+6x+9=0?
Δ=b²-4ac
Δ=6²-4*1*9
Δ=36-36
Δ=0
baskaras
x= -b+/-√Δ sobre 2a
x¹= -6÷2= -3
x²= -6÷2= -3
b)x²+x+12=0
Δ=1²-4*1*12
Δ=1-48
Δ= -47
c)7x²+x+1=0
Δ=1²-4*7*1
Δ=1-28
Δ=-27
d)x²-x-1=0
Δ=(-1²)-4*1*(-1
Δ=1+4
Δ=5
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a) x²+6x+9=0?
Δ=b²-4ac
Δ=6²-4*1*9
Δ=36-36
Δ=0
baskaras
x= -b+/-√Δ sobre 2a
x¹= -6÷2= -3
x²= -6÷2= -3
b)x²+x+12=0
Δ=b²-4ac
Δ=1²-4*1*12
Δ=1-48
Δ= -47
c)7x²+x+1=0
Δ=b²-4ac
Δ=1²-4*7*1
Δ=1-28
Δ=-27
d)x²-x-1=0
Δ=b²-4ac
Δ=(-1²)-4*1*(-1
Δ=1+4
Δ=5