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MegaWolverine
@MegaWolverine
October 2019
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Seja a função g: Reais -Reais onde g(x)= 2/1+x² calcule g(√2+1)
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newtoneinsteintesla
G(x)=2/1+x²
g(√2+1)=2/1+(√2+1)²
g(√2+1)=2/1+2+2√2+1
g(√2+1)=2/4+2√2
g(√2+1)=1/2+√2
S:1/2+√2 S: 1/2+√2.(2-√2)/(2-√2) S: 2-√2/2
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MegaWolverine
como faço pra racionalizar
newtoneinsteintesla
Multiplica pelo conjugado de 2+ raíz de 2, ou seja, 2- raíz de 2
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Lista de comentários
g(√2+1)=2/1+(√2+1)²
g(√2+1)=2/1+2+2√2+1
g(√2+1)=2/4+2√2
g(√2+1)=1/2+√2
S:1/2+√2 S: 1/2+√2.(2-√2)/(2-√2) S: 2-√2/2