A = b.h A = (5x -3) . (2x +1) A = 10x² + 5x – 6x – 3 A = 10x² - x – 3 delta = b² -4ac delta = (-1)² - 4(10)(-3) delta = 1 + 120 = 121
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A = b.h
x = -b ± √deltaA = (5x -3) . (2x +1)
A = 10x² + 5x – 6x – 3
A = 10x² - x – 3
delta = b² -4ac
delta = (-1)² - 4(10)(-3)
delta = 1 + 120 = 121
2a
x = - (-1) ± √121
2(10)
x¹ = 1 + 11 = 0,6
20
x² = 1 – 11 = -0,5
20
A = (5x -3) . (2x +1)
A = [5(0,6) – 3] . [2(0,6) +1]
A = 0 . 2,2
A = 0